Optimal. Leaf size=236 \[ -\frac{a^3 (A-B)}{80 d (a \sin (c+d x)+a)^5}-\frac{a^2 (2 A-B)}{64 d (a \sin (c+d x)+a)^4}+\frac{3 (7 A+3 B)}{256 d \left (a^2-a^2 \sin (c+d x)\right )}-\frac{5 (7 A+B)}{256 d \left (a^2 \sin (c+d x)+a^2\right )}+\frac{7 (4 A+B) \tanh ^{-1}(\sin (c+d x))}{128 a^2 d}+\frac{a (A+B)}{192 d (a-a \sin (c+d x))^3}-\frac{a (5 A-B)}{96 d (a \sin (c+d x)+a)^3}+\frac{3 A+2 B}{128 d (a-a \sin (c+d x))^2}-\frac{5 A}{64 d (a \sin (c+d x)+a)^2} \]
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Rubi [A] time = 0.278553, antiderivative size = 236, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.097, Rules used = {2836, 77, 206} \[ -\frac{a^3 (A-B)}{80 d (a \sin (c+d x)+a)^5}-\frac{a^2 (2 A-B)}{64 d (a \sin (c+d x)+a)^4}+\frac{3 (7 A+3 B)}{256 d \left (a^2-a^2 \sin (c+d x)\right )}-\frac{5 (7 A+B)}{256 d \left (a^2 \sin (c+d x)+a^2\right )}+\frac{7 (4 A+B) \tanh ^{-1}(\sin (c+d x))}{128 a^2 d}+\frac{a (A+B)}{192 d (a-a \sin (c+d x))^3}-\frac{a (5 A-B)}{96 d (a \sin (c+d x)+a)^3}+\frac{3 A+2 B}{128 d (a-a \sin (c+d x))^2}-\frac{5 A}{64 d (a \sin (c+d x)+a)^2} \]
Antiderivative was successfully verified.
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Rule 2836
Rule 77
Rule 206
Rubi steps
\begin{align*} \int \frac{\sec ^7(c+d x) (A+B \sin (c+d x))}{(a+a \sin (c+d x))^2} \, dx &=\frac{a^7 \operatorname{Subst}\left (\int \frac{A+\frac{B x}{a}}{(a-x)^4 (a+x)^6} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^7 \operatorname{Subst}\left (\int \left (\frac{A+B}{64 a^6 (a-x)^4}+\frac{3 A+2 B}{64 a^7 (a-x)^3}+\frac{3 (7 A+3 B)}{256 a^8 (a-x)^2}+\frac{A-B}{16 a^4 (a+x)^6}+\frac{2 A-B}{16 a^5 (a+x)^5}+\frac{5 A-B}{32 a^6 (a+x)^4}+\frac{5 A}{32 a^7 (a+x)^3}+\frac{5 (7 A+B)}{256 a^8 (a+x)^2}+\frac{7 (4 A+B)}{128 a^8 \left (a^2-x^2\right )}\right ) \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a (A+B)}{192 d (a-a \sin (c+d x))^3}+\frac{3 A+2 B}{128 d (a-a \sin (c+d x))^2}-\frac{a^3 (A-B)}{80 d (a+a \sin (c+d x))^5}-\frac{a^2 (2 A-B)}{64 d (a+a \sin (c+d x))^4}-\frac{a (5 A-B)}{96 d (a+a \sin (c+d x))^3}-\frac{5 A}{64 d (a+a \sin (c+d x))^2}+\frac{3 (7 A+3 B)}{256 d \left (a^2-a^2 \sin (c+d x)\right )}-\frac{5 (7 A+B)}{256 d \left (a^2+a^2 \sin (c+d x)\right )}+\frac{(7 (4 A+B)) \operatorname{Subst}\left (\int \frac{1}{a^2-x^2} \, dx,x,a \sin (c+d x)\right )}{128 a d}\\ &=\frac{7 (4 A+B) \tanh ^{-1}(\sin (c+d x))}{128 a^2 d}+\frac{a (A+B)}{192 d (a-a \sin (c+d x))^3}+\frac{3 A+2 B}{128 d (a-a \sin (c+d x))^2}-\frac{a^3 (A-B)}{80 d (a+a \sin (c+d x))^5}-\frac{a^2 (2 A-B)}{64 d (a+a \sin (c+d x))^4}-\frac{a (5 A-B)}{96 d (a+a \sin (c+d x))^3}-\frac{5 A}{64 d (a+a \sin (c+d x))^2}+\frac{3 (7 A+3 B)}{256 d \left (a^2-a^2 \sin (c+d x)\right )}-\frac{5 (7 A+B)}{256 d \left (a^2+a^2 \sin (c+d x)\right )}\\ \end{align*}
Mathematica [A] time = 1.37362, size = 160, normalized size = 0.68 \[ \frac{210 (4 A+B) \tanh ^{-1}(\sin (c+d x))-\frac{2 \left (105 (4 A+B) \sin ^7(c+d x)+210 (4 A+B) \sin ^6(c+d x)-175 (4 A+B) \sin ^5(c+d x)-560 (4 A+B) \sin ^4(c+d x)-49 (4 A+B) \sin ^3(c+d x)+462 (4 A+B) \sin ^2(c+d x)+183 (4 A+B) \sin (c+d x)+48 (3 B-8 A)\right )}{(\sin (c+d x)-1)^3 (\sin (c+d x)+1)^5}}{3840 a^2 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.141, size = 359, normalized size = 1.5 \begin{align*} -{\frac{7\,\ln \left ( \sin \left ( dx+c \right ) -1 \right ) A}{64\,d{a}^{2}}}-{\frac{7\,\ln \left ( \sin \left ( dx+c \right ) -1 \right ) B}{256\,d{a}^{2}}}+{\frac{3\,A}{128\,d{a}^{2} \left ( \sin \left ( dx+c \right ) -1 \right ) ^{2}}}+{\frac{B}{64\,d{a}^{2} \left ( \sin \left ( dx+c \right ) -1 \right ) ^{2}}}-{\frac{A}{192\,d{a}^{2} \left ( \sin \left ( dx+c \right ) -1 \right ) ^{3}}}-{\frac{B}{192\,d{a}^{2} \left ( \sin \left ( dx+c \right ) -1 \right ) ^{3}}}-{\frac{21\,A}{256\,d{a}^{2} \left ( \sin \left ( dx+c \right ) -1 \right ) }}-{\frac{9\,B}{256\,d{a}^{2} \left ( \sin \left ( dx+c \right ) -1 \right ) }}-{\frac{5\,A}{64\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) ^{2}}}-{\frac{A}{80\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) ^{5}}}+{\frac{B}{80\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) ^{5}}}-{\frac{A}{32\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) ^{4}}}+{\frac{B}{64\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) ^{4}}}-{\frac{5\,A}{96\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) ^{3}}}+{\frac{B}{96\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) ^{3}}}+{\frac{7\,\ln \left ( 1+\sin \left ( dx+c \right ) \right ) A}{64\,d{a}^{2}}}+{\frac{7\,B\ln \left ( 1+\sin \left ( dx+c \right ) \right ) }{256\,d{a}^{2}}}-{\frac{35\,A}{256\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) }}-{\frac{5\,B}{256\,d{a}^{2} \left ( 1+\sin \left ( dx+c \right ) \right ) }} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.05955, size = 340, normalized size = 1.44 \begin{align*} -\frac{\frac{2 \,{\left (105 \,{\left (4 \, A + B\right )} \sin \left (d x + c\right )^{7} + 210 \,{\left (4 \, A + B\right )} \sin \left (d x + c\right )^{6} - 175 \,{\left (4 \, A + B\right )} \sin \left (d x + c\right )^{5} - 560 \,{\left (4 \, A + B\right )} \sin \left (d x + c\right )^{4} - 49 \,{\left (4 \, A + B\right )} \sin \left (d x + c\right )^{3} + 462 \,{\left (4 \, A + B\right )} \sin \left (d x + c\right )^{2} + 183 \,{\left (4 \, A + B\right )} \sin \left (d x + c\right ) - 384 \, A + 144 \, B\right )}}{a^{2} \sin \left (d x + c\right )^{8} + 2 \, a^{2} \sin \left (d x + c\right )^{7} - 2 \, a^{2} \sin \left (d x + c\right )^{6} - 6 \, a^{2} \sin \left (d x + c\right )^{5} + 6 \, a^{2} \sin \left (d x + c\right )^{3} + 2 \, a^{2} \sin \left (d x + c\right )^{2} - 2 \, a^{2} \sin \left (d x + c\right ) - a^{2}} - \frac{105 \,{\left (4 \, A + B\right )} \log \left (\sin \left (d x + c\right ) + 1\right )}{a^{2}} + \frac{105 \,{\left (4 \, A + B\right )} \log \left (\sin \left (d x + c\right ) - 1\right )}{a^{2}}}{3840 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.78837, size = 782, normalized size = 3.31 \begin{align*} \frac{420 \,{\left (4 \, A + B\right )} \cos \left (d x + c\right )^{6} - 140 \,{\left (4 \, A + B\right )} \cos \left (d x + c\right )^{4} - 56 \,{\left (4 \, A + B\right )} \cos \left (d x + c\right )^{2} + 105 \,{\left ({\left (4 \, A + B\right )} \cos \left (d x + c\right )^{8} - 2 \,{\left (4 \, A + B\right )} \cos \left (d x + c\right )^{6} \sin \left (d x + c\right ) - 2 \,{\left (4 \, A + B\right )} \cos \left (d x + c\right )^{6}\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) - 105 \,{\left ({\left (4 \, A + B\right )} \cos \left (d x + c\right )^{8} - 2 \,{\left (4 \, A + B\right )} \cos \left (d x + c\right )^{6} \sin \left (d x + c\right ) - 2 \,{\left (4 \, A + B\right )} \cos \left (d x + c\right )^{6}\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (105 \,{\left (4 \, A + B\right )} \cos \left (d x + c\right )^{6} - 140 \,{\left (4 \, A + B\right )} \cos \left (d x + c\right )^{4} - 84 \,{\left (4 \, A + B\right )} \cos \left (d x + c\right )^{2} - 256 \, A - 64 \, B\right )} \sin \left (d x + c\right ) - 128 \, A - 512 \, B}{3840 \,{\left (a^{2} d \cos \left (d x + c\right )^{8} - 2 \, a^{2} d \cos \left (d x + c\right )^{6} \sin \left (d x + c\right ) - 2 \, a^{2} d \cos \left (d x + c\right )^{6}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.6953, size = 348, normalized size = 1.47 \begin{align*} \frac{\frac{420 \,{\left (4 \, A + B\right )} \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right )}{a^{2}} - \frac{420 \,{\left (4 \, A + B\right )} \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right )}{a^{2}} + \frac{10 \,{\left (308 \, A \sin \left (d x + c\right )^{3} + 77 \, B \sin \left (d x + c\right )^{3} - 1050 \, A \sin \left (d x + c\right )^{2} - 285 \, B \sin \left (d x + c\right )^{2} + 1212 \, A \sin \left (d x + c\right ) + 363 \, B \sin \left (d x + c\right ) - 478 \, A - 163 \, B\right )}}{a^{2}{\left (\sin \left (d x + c\right ) - 1\right )}^{3}} - \frac{3836 \, A \sin \left (d x + c\right )^{5} + 959 \, B \sin \left (d x + c\right )^{5} + 21280 \, A \sin \left (d x + c\right )^{4} + 5095 \, B \sin \left (d x + c\right )^{4} + 47960 \, A \sin \left (d x + c\right )^{3} + 10790 \, B \sin \left (d x + c\right )^{3} + 55360 \, A \sin \left (d x + c\right )^{2} + 11230 \, B \sin \left (d x + c\right )^{2} + 33260 \, A \sin \left (d x + c\right ) + 5435 \, B \sin \left (d x + c\right ) + 8608 \, A + 667 \, B}{a^{2}{\left (\sin \left (d x + c\right ) + 1\right )}^{5}}}{15360 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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